Cambridge IGCSE Mathematics 0580 · Algebra and graphs

Proportion

Direct and inverse proportion written in algebra, with the symbol ∝: linear, square, cube, square root and cube root proportion, finding the constant k and using the formula to find unknown quantities.

E2.8Extended onlyFree lesson
What the syllabus says

E2.8 (Extended)

  • Express direct and inverse proportion in algebraic terms and use this form of expression to find unknown quantities.

Notes and examples

  • Includes linear, square, square root, cube and cube root proportion.
  • Knowledge of proportional symbol (∝) is required.

Quoted from the Cambridge IGCSE Mathematics 0580 syllabus for 2025 to 2027.

Direct proportion Extended

Two quantities are directly proportional when multiplying one of them by any number multiplies the other by the same number: double one and the other doubles, divide one by 10 and the other is divided by 10.

We write y∝x, read "y is proportional to x". The symbol ∝ means "is proportional to". It can always be replaced by "=k×", where k is a fixed number called the constant of proportionality:
y∝xmeansy=kx

The cost of fuel is proportional to the number of litres bought, and k is the price of one litre. The graph of y=kx is a straight line through the origin, as in the diagram below, where k=2.5. Every point on it has yx=2.5, which is why a straight line through the origin always means direct proportion.

xy1234562468101214160(2, 5)(4, 10)

Proportion to a power or a root Extended

One quantity can be proportional to a power or a root of another. The syllabus includes five kinds:

  • y∝x: y=kx
  • y∝x2: y=kx2, for example the area of a shape is proportional to the square of its length when the shape stays similar;
  • y∝x3: y=kx3, for example the mass of a solid ball is proportional to the cube of its radius;
  • y∝x: y=kx;
  • y∝x3: y=kx3.

Read the wording carefully: "y is proportional to the square of x" is y∝x2, while "y is proportional to the square root of x" is y∝x. The power changes what doubling does. If x doubles, then x2 is multiplied by 4 and x3 by 8, but x is multiplied by only 2≈1.41.

Inverse proportion Extended

Two quantities are inversely proportional when multiplying one by a number divides the other by the same number: double one and the other halves. We write
y∝1xwhich meansy=kx
Equivalently xy=k: the product stays the same. If 4 workers take 6 days to paint a building, then k=24 worker-days, so 8 workers take 3 days and 3 workers take 8 days.

Inverse proportion also comes with powers and roots: y∝1x2 (the inverse square law, y=kx2), y∝1x3, y∝1x and y∝1x3. "Inversely proportional to the square of x" means y=kx2.

The graph of y=kx for positive x is a curve that gets closer and closer to both axes but never touches them.

The method: find k, then use it Extended

Almost every proportion question follows the same steps:

  1. Write the statement with ∝, for example y∝x2.
  2. Replace ∝ by "=k×": y=kx2.
  3. Substitute the pair of values the question gives you to find k.
  4. Write the formula with the value of k in it. Many questions award a mark for this formula on its own.
  5. Use the formula to find the unknown quantity. If you are finding x, rearrange: for y=kx2, x=yk.

Finding k first is what makes the method reliable: once you have the formula, every later part is just substitution.

Worked example 1 Extended

y is proportional to the square of x. When x=3, y=45. (a) Find a formula for y in terms of x. (b) Find y when x=4. (c) Find the positive value of x when y=125.

  1. (a) y∝x2, so y=kx2.

  2. Substitute x=3, y=45: 45=k×9, so k=5. The formula is y=5x2.

  3. (b) y=5×42=5×16=80.

  4. (c) 125=5x2, so x2=25 and x=5, taking the positive root as the question asks.

Answer: (a) y=5x2 (b) 80 (c) 5

Worked example 2 Extended

y is inversely proportional to the square root of x. When x=16, y=6. (a) Find y when x=9. (b) Find x when y=3.

  1. y∝1x, so y=kx.

  2. Substitute x=16, y=6: 6=k4, so k=24 and y=24x.

  3. (a) y=249=243=8.

  4. (b) 3=24x, so x=8 and x=64.

Answer: (a) 8 (b) 64

Worked example 3 Extended

The time, t hours, for a journey is inversely proportional to the average speed, v km/h. At an average speed of 60 km/h the journey takes 3.5 hours. (a) How long does the journey take at 75 km/h? (b) What average speed is needed to make the journey in 2 hours?

  1. t=kv. Substitute: 3.5=k60, so k=210. (This is the length of the journey, 210 km.)

  2. (a) t=21075=2.8 hours, which is 2 hours 48 minutes.

  3. (b) 2=210v, so v=105 km/h.

Answer: (a) 2.8 hours (b) 105 km/h

Using multipliers Extended

Some questions only ask what happens to one quantity when the other changes. You do not need k for these: apply the change to the power or root.

  • y∝x2 and x is multiplied by 3: y is multiplied by 32=9.
  • y∝x3 and x is halved: y is multiplied by (12)3=18.
  • y∝1x2 and x is doubled: y is multiplied by 122=14.

Percentage changes work the same way through the multiplier. If y∝x2 and x increases by 10%, the multiplier for x is 1.1, so the multiplier for y is 1.12=1.21, an increase of 21%, not 20%.

Check yourself Extended

y is proportional to x3. When x=2, y=16. Find y when x=3.

Answer it in the portal, where your answer is checked as you type →

Check yourself Extended

y is inversely proportional to x2. When x=4, y=5. Find y when x=10.

Answer it in the portal, where your answer is checked as you type →

Key points

  • ∝ means "is proportional to"; replace it by "=k×".

  • Direct: y=kx, kx2, kx3, kx or kx3. Inverse: divide k by the same quantity instead.

  • Find k from the given pair, write the formula, then substitute.

  • To find x, rearrange the formula: undo a square with a square root, a cube with a cube root, and so on.

  • For "what happens to y" questions, apply the multiplier to the power: tripling x multiplies x2 by 9.

Where marks are lost Extended

  • Using y=kx when the question says "proportional to the square of x".

  • Finding k by dividing y by x when the relationship is y=kx2: divide by x2.

  • Treating "inversely proportional" as direct proportion, so y grows when it should shrink.

  • Stopping at x2=25 instead of square rooting, or forgetting to cube when x3=3.

  • Thinking that a 10% increase in x gives a 20% increase in x2: the multiplier is 1.12=1.21.

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An original lesson written to the Cambridge IGCSE Mathematics 0580 syllabus (2025 to 2027). The worked examples and questions are our own, not Cambridge questions. Back to every IGCSE Mathematics 0580 lesson.