Group 2
Contents: 8 sections
The elements and the trend
Group 2 runs beryllium, magnesium, calcium, strontium, barium. Each has two electrons in its outer s sub-shell and loses both to form a 2+ ion.
Reactivity increases down the group, and the reason is the same one that runs through the whole topic: the outer electrons are further from the nucleus and better shielded, so the ionisation energies fall and the metal loses its electrons more readily.
That single trend explains almost everything here, so it is worth stating in full whenever a question asks why.
Reactions of the elements
With oxygen, they burn to the oxide:
2Mg + O₂ → 2MgO
Magnesium burns with a brilliant white flame. The vigour increases down the group.
With water, the trend is clear and often examined:
- Magnesium reacts very slowly with cold water, giving Mg(OH)₂ and hydrogen. With steam it reacts rapidly to give MgO and hydrogen instead, which is a different product and a common trap.
- Calcium reacts steadily with cold water, fizzing, to give Ca(OH)₂ and hydrogen.
- Barium reacts rapidly.
Ca + 2H₂O → Ca(OH)₂ + H₂
With dilute acids, all react to give a salt and hydrogen, faster down the group:
Mg + 2HCl → MgCl₂ + H₂
Calcium with sulfuric acid is a useful exception to remember: the calcium sulfate formed is only slightly soluble, coats the metal and the reaction slows and stops.
Oxides and hydroxides
The oxides are basic. With water they give hydroxides:
CaO + H₂O → Ca(OH)₂
With dilute acid they give a salt and water:
MgO + 2HCl → MgCl₂ + H₂O
Calcium hydroxide solution is limewater, and the test for carbon dioxide is that it turns limewater milky, because insoluble calcium carbonate is formed.
Solubility trends
Two trends run in opposite directions, and mixing them up is the most common error in the topic.
| Compound | Trend down the group |
|---|---|
| Hydroxides | Solubility increases |
| Sulfates | Solubility decreases |
So Mg(OH)₂ is only slightly soluble while Ba(OH)₂ dissolves readily, whereas MgSO₄ is very soluble while BaSO₄ is essentially insoluble.
The insolubility of barium sulfate is the basis of the test for sulfate ions: add dilute hydrochloric acid, then barium chloride solution, and a white precipitate confirms sulfate. The acid is added first to remove carbonate, which would also give a white precipitate and a false positive.
Barium sulfate is also used as a "barium meal" in medical imaging. Barium ions are toxic, but the sulfate is so insoluble that almost none dissolves.
Thermal decomposition
Group 2 carbonates decompose on heating to the oxide and carbon dioxide:
CaCO₃ → CaO + CO₂
Group 2 nitrates decompose to the oxide, nitrogen dioxide and oxygen:
2Ca(NO₃)₂ → 2CaO + 4NO₂ + O₂
Brown fumes of NO₂ are the observation to expect.
The trend, and why
Thermal stability increases down the group, so the compounds need a higher temperature to decompose as you go down.
The explanation is polarisation, and the reasoning is worth setting out in full because it earns several marks:
- Going down the group the cation gets larger, while the charge stays 2+.
- So the charge density of the cation falls.
- A cation of lower charge density polarises the carbonate or nitrate anion less, distorting its electron cloud less.
- Less distortion means the bonds within the anion are weakened less, so more energy is needed to break them.
Magnesium carbonate therefore decomposes at a lower temperature than barium carbonate.
The same argument explains why Group 1 carbonates are more stable than Group 2 ones: a 1+ ion has a lower charge density than a 2+ ion of similar size, so it polarises less.
Flame colours
The Group 2 metals give characteristic flame colours, used to identify them:
| Ion | Flame colour |
|---|---|
| Ca²⁺ | Brick red |
| Sr²⁺ | Red |
| Ba²⁺ | Apple green |
Magnesium gives no colour. The colour arises because heat promotes an electron to a higher energy level, and light of a particular wavelength is emitted as it falls back.
Common mistakes
- Getting the two solubility trends the wrong way round. Hydroxides become more soluble down the group; sulfates become less.
- Saying magnesium reacts vigorously with cold water. It is very slow, and only fast with steam.
- Giving Mg(OH)₂ as the product with steam. Steam gives MgO, not the hydroxide.
- Explaining thermal stability by ionisation energy. The reason is polarisation by the cation.
- Forgetting to acidify before adding barium chloride in the sulfate test.
- Saying barium compounds are safe because barium sulfate is used medically. It is safe only because it is so insoluble.
Check you have it
Question 1
Element X requires strong heating to react with oxygen.
Element X reacts with chlorine to give a covalently-bonded chloride.
What could be the identity of element X?
Answer: D.
A covalent chloride means the element is on the right of the period. Sodium and magnesium form ionic chlorides, so A and C are out.
Requiring strong heating to react with oxygen separates the remaining two. Silicon is notoriously unreactive towards oxygen: it needs very high temperatures, which is why silicon stays intact in a chip and why sand is stable. Phosphorus is the opposite: white phosphorus ignites spontaneously in air, and even red phosphorus catches easily.
So silicon, which is D.
Silicon's chloride, SiCl₄, is simple molecular and fumes in moist air as it hydrolyses:
SiCl₄ + 2H₂O → SiO₂ + 4HCl
which confirms the second clue.
Silicon is the element that fails to fit the tidy story of Period 3 in this one respect. It is a semiconductor rather than a metal or a non-metal, its oxide is giant covalent rather than simple molecular, and it is far less reactive than either of its neighbours. 'Requires strong heating' is the phrase Cambridge uses to point at it.
Question 2
In Group 2 of the Periodic Table, the properties of the elements and their compounds show regular change down the group.
Which property shows a decrease from magnesium to barium?
Answer: D.
D is the answer. The solubility of the sulfates decreases down the group: MgSO₄ is very soluble, CaSO₄ is only slightly so, and BaSO₄ is insoluble enough to be used as the test for sulfate ions and as a barium meal in medicine.
C increases. The hydroxides run the opposite way to the sulfates: Mg(OH)₂ is nearly insoluble while Ba(OH)₂ dissolves freely.
A and B both increase. Thermal stability rises down the group, so both the carbonates and the nitrates need a higher temperature to decompose as you descend.
The hydroxide and sulfate trends run in opposite directions, and the reason is worth carrying. Dissolving is a contest between the lattice energy holding the solid together and the hydration enthalpy released when the ions are surrounded by water. Going down the group the cation gets bigger, so both fall. With the small hydroxide ion the lattice energy falls faster, so solubility rises; with the large sulfate ion the lattice energy barely changes and the hydration enthalpy is what falls, so solubility drops.
Hydroxides up, sulfates down is the pair to remember, and this question is asking for the one that goes down.
Question 3
A sample consisting of 1.0 mol of anhydrous calcium nitrate is completely decomposed by strong heating.
What is the total amount of gas produced in this reaction?
Answer: C.
2Ca(NO₃)₂ → 2CaO + 4NO₂ + O₂
Halve it so that it describes one mole:
Ca(NO₃)₂ → CaO + 2NO₂ + ½O₂
The calcium oxide is a solid and is not gas. The gases are 2 mol of NO₂ and 0.5 mol of O₂:
2.0 + 0.5 = 2.5 mol, which is C.
D, 3.0 mol, comes from counting the CaO as a product alongside the gases, and the question asks specifically for gas.
B, 2.0 mol, is the nitrogen dioxide alone, forgetting the oxygen.
The 2 : 0.5 split follows from the formula rather than needing to be memorised. Each of the two nitrate ions, NO₃⁻, becomes one NO₂ molecule, which accounts for the 2. That leaves one oxygen atom over from each nitrate and one more from the electrons balancing, and those pair up into half a molecule of O₂.
The brown NO₂ is what makes this decomposition visible, and the O₂ is what relights a glowing splint.
What the syllabus asks for on this topicSyllabus points
Syllabus points
- Describe the reactions of Group 2 elements with oxygen, water and dilute acids.
- Describe the behaviour of Group 2 oxides and hydroxides with water and with dilute acid.
- Explain the trend in solubility of the Group 2 hydroxides and sulfates.
- Describe and explain the thermal decomposition of Group 2 carbonates and nitrates.
- Explain the trends using ionic radius and charge density.
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