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CIE 9701 Chemistry · AS · Topic 20

Polymerisation

Clear, syllabus-mapped CIE 9701 Chemistry revision notes on polymerisation: explanations, worked examples and exam technique, then a free targeted practice drill.

CIE 9701 ChemistryASFree revision notes
Contents: 6 sections

Syllabus points

Addition polymerisation

An addition polymer forms when many alkene monomers join by the opening of their C=C double bonds. Nothing else is produced, so the polymer has the same empirical formula as the monomer.

n CH₂=CH₂ → -(CH₂-CH₂)ₙ-

MonomerPolymer
EthenePoly(ethene)
PropenePoly(propene)
ChloroethenePoly(chloroethene), PVC
PhenylethenePoly(phenylethene), polystyrene
TetrafluoroethenePTFE

Deducing the repeat unit

From the monomer: draw the C=C, open the double bond, and put a bond out from each carbon. Keep all the side groups exactly where they were.

The repeat unit must be drawn with the two bonds sticking out and the square brackets with the n. A common way to lose the mark is to draw the repeat unit with a double bond still in it, which would mean the polymerisation had not happened.

Deducing the monomer

Working backwards from a section of polymer is the harder direction and appears often.

  1. Find the repeating pattern in the chain. The backbone of an addition polymer is all carbon, and the repeat unit is two carbon atoms long.
  2. Take one repeat unit of two carbons.
  3. Put the double bond back between them and remove the two spare bonds.

So a chain drawn as -CH₂-CH(CH₃)-CH₂-CH(CH₃)- has the repeat unit -CH₂-CH(CH₃)-, and the monomer is CH₂=CH(CH₃), which is propene.

The step people get wrong is taking a repeat unit of the wrong length. Count carefully until the pattern genuinely repeats.

Condensation polymerisation

A condensation polymer forms when monomers join with the loss of a small molecule, usually water or HCl. Each monomer needs two functional groups, one at each end, so that the chain can grow in both directions.

Polyesters

Made from a diol and a dicarboxylic acid, joined by ester links with the loss of water. Terylene, also called PET, is the standard example.

The ester link is -COO-.

Polyamides

Made from a diamine and a dicarboxylic acid, joined by amide links with the loss of water. Nylon is the example, and proteins are natural polyamides.

The amide link is -CONH-.

An acyl chloride can be used in place of the acid, in which case HCl is lost rather than water, and the reaction is faster.

Deducing the monomers

Find the linkage in the chain and break it, then add back what was lost:

Adding water back is the step that gets forgotten, and it leaves the answer one OH and one H short.

Comparing the two

AdditionCondensation
MonomerOne, an alkeneTwo, each with two functional groups
Small molecule lostNoneWater or HCl
BackboneCarbon onlyContains C-O or C-N links
Hydrolysed?NoYes

The last row is the most important, and it explains the environmental difference.

An addition polymer has a backbone of nothing but strong, non-polar carbon-carbon bonds. There is no δ+ carbon for a nucleophile to attack, so it is not hydrolysed and is chemically inert. That is exactly what makes poly(ethene) useful and also what makes it persist in the environment for centuries.

A condensation polymer has polar ester or amide links in its backbone, which can be hydrolysed by acid or alkali, and slowly by water. So polyesters and polyamides are biodegradable, at least in principle.

Disposal

Several routes, each with a real drawback:

The judgement the syllabus expects is that no single route solves it, and that the properties which make polymers useful, their durability and inertness, are the same properties that make disposal difficult.

Common mistakes

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