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CIE 9700 Biology · A Level · Topic 12

Energy and respiration

Clear, syllabus-mapped CIE 9700 Biology revision notes on energy and respiration: explanations, worked examples and exam technique, then a free targeted practice drill.

CIE 9700 BiologyA LevelFree revision notes
Contents: 12 sections

Every objective in this topic is printed under the heading "A Level subject content" in the 9700 syllabus, so all of it is A Level and none of it is AS. It is examined on Paper 4, and the practical objectives feed Paper 5. Paper 1 is the 40-question AS multiple-choice paper, so this topic never appears there, which is why the multiple-choice practice on this site has nothing tagged to it.

Syllabus points

12.1 Energy

12.2 Respiration

Why a cell needs energy at all

A cell is a system that is constantly being pushed away from equilibrium, and every push costs energy. Three examples carry the whole objective:

Energy is also spent on maintaining body temperature in a mammal and on bioluminescence in a few organisms, but the three above are the ones the syllabus names.

Why ATP is the universal energy currency

ATP is adenine plus ribose plus three phosphate groups. Hydrolysis of the terminal phosphate gives ADP, inorganic phosphate, and about 30.5 kJ per mole.

The word to hold on to is currency, not store. ATP is not where a cell keeps its energy; glycogen and lipid are. ATP is what a cell trades in, and the features that suit it to that job are these:

ATP is made in two distinct ways, and the syllabus wants both named:

Respiratory substrates and their energy values

SubstrateEnergy value / kJ g⁻¹Why
Lipid39Long hydrocarbon chains, so many carbon-hydrogen bonds and very little oxygen already in the molecule
Protein17Similar to carbohydrate once the amino group is removed
Carbohydrate16Already partly oxidised, so fewer hydrogens to hand to the carriers

The reason is worth stating properly, because "lipids have more energy" earns nothing. What is actually being oxidised is hydrogen. Each pair of hydrogen atoms handed to NAD ends up driving proton pumping and therefore ATP synthesis. A lipid molecule is almost entirely carbon and hydrogen, so per gram it supplies far more hydrogen than a carbohydrate, which already carries an oxygen for every carbon.

Respiratory quotient

RQ is the ratio of carbon dioxide molecules given out to oxygen molecules taken in:

RQ = molecules of CO₂ produced / molecules of O₂ used

Worked example, carbohydrate. For the complete oxidation of glucose:

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O

RQ = 6 / 6 = 1.0

Worked example, lipid. Oleic acid burns as:

C₁₈H₃₄O₂ + 25.5O₂ → 18CO₂ + 17H₂O

RQ = 18 / 25.5 = 0.71

Protein works out at roughly 0.9. Proteins are only used as a respiratory substrate when carbohydrate and lipid are short, because the amino group has to be removed first by deamination in the liver and converted to urea, which itself costs energy.

So the RQ tells you what is being respired:

RQInterpretation
1.0Carbohydrate
about 0.9Protein
about 0.7Lipid
above 1.0Some anaerobic respiration is happening as well, so carbon dioxide is being released without oxygen being taken in

An RQ above 1.0 is the case worth understanding rather than memorising. In ethanol fermentation, pyruvate is decarboxylated and carbon dioxide comes off with no oxygen consumed at all, so the numerator rises while the denominator does not.

Measuring RQ with a respirometer

A simple respirometer is a sealed tube holding the organism, a manometer to read a volume change, and a control tube identical in every way except that it holds glass beads of the same mass instead of a living organism. Both sit in the same water bath so that a change in room temperature or atmospheric pressure moves both arms equally and cancels out.

The trick is to run the experiment twice:

  1. With potassium hydroxide in the tube. KOH absorbs all the carbon dioxide produced, so the only volume change is the oxygen taken in. The manometer fluid moves towards the organism, and the distance gives the oxygen uptake.
  2. Without potassium hydroxide. Now oxygen is being removed and carbon dioxide added, so the reading is the difference between them.

Worked example. Germinating seeds take up oxygen at 0.60 cm³ min⁻¹ when KOH is present. With the KOH removed, the fluid still moves towards the seeds, at 0.15 cm³ min⁻¹.

The second reading is oxygen used minus carbon dioxide released, so:

carbon dioxide released = 0.60 - 0.15 = 0.45 cm³ min⁻¹

RQ = 0.45 / 0.60 = 0.75

which points at lipid as the main substrate, exactly what you would expect of a seed living on a stored oil reserve.

The four stages of aerobic respiration

StageWhereMain products
GlycolysisCytoplasm2 pyruvate, net 2 ATP, 2 reduced NAD
Link reactionMitochondrial matrixAcetyl coenzyme A, CO₂, reduced NAD
Krebs cycleMitochondrial matrixCO₂, reduced NAD, reduced FAD, ATP
Oxidative phosphorylationInner mitochondrial membraneATP, water

Learn the locations as carefully as the chemistry. Questions ask them directly, and the commonest error is to place glycolysis inside the mitochondrion. Glycolysis is in the cytoplasm, which is why a red blood cell, which has no mitochondria at all, can still respire glucose anaerobically.

Glycolysis

Glucose is phosphorylated twice, using two ATP, to give hexose bisphosphate. That seems perverse when the point of the pathway is to make ATP, but phosphorylation is what makes the glucose reactive enough to be split, and it traps it inside the cell.

Fructose 1,6-bisphosphate (6C) is then split into two triose phosphate molecules (3C). Each is oxidised to pyruvate (3C). The oxidation is a dehydrogenation: the hydrogen removed is taken up by NAD, giving reduced NAD, and four ATP are made by substrate-linked phosphorylation.

Net per glucose: 2 ATP, 2 reduced NAD, 2 pyruvate. Four made minus two invested.

The link reaction

When oxygen is available, pyruvate is actively transported into the mitochondrial matrix. Two things then happen to it.

What remains is a 2C acetyl group, and coenzyme A picks it up to form acetyl coenzyme A. Coenzyme A is a carrier: it delivers the acetyl group to the Krebs cycle and is released unchanged.

This happens twice per glucose, because glycolysis produced two pyruvate.

The Krebs cycle

Acetyl coenzyme A hands its 2C fragment to oxaloacetate (4C) to form citrate (6C). Citrate is then converted back to oxaloacetate in a series of small steps, each catalysed by its own enzyme. Across those steps:

Per glucose the cycle turns twice, so double all of that.

Oxaloacetate is regenerated, which is what makes this a cycle. It is not consumed, so a small amount keeps working indefinitely.

Oxidative phosphorylation

All that reduced NAD and reduced FAD is the point of the first three stages. It now delivers hydrogen to carriers in the inner mitochondrial membrane, and the sequence runs:

  1. Hydrogen atoms split into protons and electrons.
  2. The energetic electrons pass along the electron transport chain, releasing energy at each transfer.
  3. That energy is used to transfer protons from the matrix into the intermembrane space, building a proton gradient and therefore a difference in both concentration and charge across the inner membrane.
  4. Protons flow back into the matrix by facilitated diffusion through ATP synthase, and the energy of that flow drives the synthesis of ATP from ADP and phosphate. This is chemiosmosis.
  5. Oxygen is the final electron acceptor. It combines with the electrons and the protons to form water.

Reduced NAD delivers its electrons earlier in the chain than reduced FAD does, so each reduced NAD drives more proton pumping and yields more ATP than each reduced FAD. The syllabus does not want a total ATP figure, so do not spend revision time on whether the answer is 36 or 38; it wants the mechanism.

The reason a lack of oxygen stops everything is worth thinking through. Without a final acceptor, electrons back up along the chain, the carriers stay reduced, no protons are pumped, and, most importantly, NAD is never regenerated. The link reaction and the Krebs cycle then halt for want of oxidised NAD, not for want of oxygen directly.

Mitochondrial structure and function

Cells with high energy demands, such as muscle fibres, liver cells and the cells of the proximal convoluted tubule, have many mitochondria with densely packed cristae. That is a favourite question: relate a number of mitochondria in a micrograph to the function of the tissue.

Anaerobic respiration

Without oxygen, only glycolysis can run, and it can only keep running if NAD is regenerated. Both fermentation pathways exist to do exactly that.

In mammals, lactate fermentation:

pyruvate + reduced NAD → lactate + NAD

In yeast, ethanol fermentation:

pyruvate → ethanal + CO₂, then ethanal + reduced NAD → ethanol + NAD

The yield is 2 ATP per glucose, against a great deal more in aerobic conditions. The reason is simple once stated: in anaerobic conditions the link reaction, the Krebs cycle and oxidative phosphorylation do not run, so the hydrogen carried by reduced NAD is never used to pump protons. Instead of being oxidised, it is dumped onto pyruvate. All that energy stays locked in the lactate or the ethanol, which is why ethanol still burns.

Note the difference between the two products. Lactate can be carried in the blood to the liver and oxidised later, so a mammal repays an oxygen debt. Ethanol cannot be recovered, and it is toxic, which is why yeast fermentation stops at around 15 per cent ethanol.

Rice as an adaptation to flooding

Rice grows with its roots submerged, where oxygen diffuses roughly ten thousand times more slowly than in air. Three adaptations are named:

Investigating rate of respiration

Redox indicators. DCPIP and methylene blue are blue when oxidised and colourless when reduced. Add one to a yeast suspension with a substrate, and the dehydrogenations of respiration reduce the dye. The time taken for the colour to disappear is the measure: a shorter time means a faster rate, so 1/t is proportional to rate. Vary temperature, or vary substrate concentration, and keep everything else the same.

Respirometers with temperature. Place the respirometer in water baths at a range of temperatures, allow time to equilibrate at each, and measure the oxygen uptake per unit time per gram of organism. Rate rises with temperature to an optimum and then falls sharply as the respiratory enzymes denature.

Common mistakes

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