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CIE 0625 Physics · IGCSE · Topic 1.1

Physical quantities and measurement techniques

Clear, syllabus-mapped CIE 0625 Physics revision notes on physical quantities and measurement techniques: explanations, worked examples and exam technique, then a free targeted practice drill.

CIE 0625 PhysicsIGCSEFree revision notes
Contents: 8 sections

Cambridge IGCSE Physics 0625 · Core and Extended

Syllabus points

Choosing the instrument

Each quantity has an instrument that reads it directly, and exam questions turn on that word more often than on anything else.

QuantityInstrumentTypical smallest division
Length, a few centimetresRuler1 mm
Length, small and preciseMicrometer screw gauge0.01 mm
Volume of a liquidMeasuring cylinder1 or 2 cm³
MassBalance0.1 g or 0.01 g
TimeStopwatch0.01 s

A balance gives mass in grams. A newton meter gives weight in newtons. Everyday speech treats these as the same and physics does not, so a question asking for mass is not answered by a spring balance.

Reading a scale

Before reading anything, work out what one small division is worth. Count the small divisions between two labelled marks and divide.

If a measuring cylinder is labelled every 10 cm³ and there are five small divisions between labels, each small division is 2 cm³, and a reading three divisions above the 10 mark is 16 cm³, not 13 cm³. Assuming every small division is worth 1 is the single most common way to lose this mark.

Read a liquid level at the bottom of the meniscus, with your eye level with the surface. Looking from above or below introduces a parallax error.

Volume of an irregular solid

A ruler is useless on a stone, so use displacement.

  1. Part fill a measuring cylinder and read the level.
  2. Lower the object in until it is fully submerged.
  3. Read the new level.
  4. The volume of the object is the difference between the two readings.

The quantity you want is always the rise, never the final reading. A question that gives you a starting volume is telling you to subtract it.

If the object floats, hold it under with a sinker: measure the sinker alone first, then the sinker and the object together, and subtract.

Repeating and averaging

A single reading carries your reaction error in full. Repeating the measurement and taking a mean spreads that error out and gives a better estimate.

For a pendulum, do not time one swing. Time 20 oscillations, then divide by 20:

Both divisions are needed and both are easy to forget. Timing many swings works because your reaction error, perhaps 0.2 s, is shared across 20 periods instead of landing on one.

The same idea gives the thickness of one sheet of paper: measure the thickness of 100 sheets with a ruler and divide by 100.

Worked example. A pendulum takes 17.6 s, 19.8 s, 17.6 s and 18.6 s for 20 oscillations. Find the period.

Mean time for 20 = (17.6 + 19.8 + 17.6 + 18.6) / 4 = 73.6 / 4 = 18.4 s. Period = 18.4 / 20 = 0.92 s.

Note that averaging first and dividing second is not the same as picking one reading. Repeating is pointless if you then use a single result.

Scalars and vectors

The distinction matters whenever direction can change. Momentum is a vector, which is why two objects can approach each other and both end up stationary without any momentum disappearing: the two momenta were opposite in sign and cancelled.

Adding vectors

Two vectors are added head to tail: draw the first, start the second at the tip of the first, and the resultant runs from the tail of the first to the head of the last.

Drawn from the same point instead, complete the parallelogram and the resultant is the diagonal from that point.

Two checks catch most errors:

Forces at right angles

When the two vectors are perpendicular, the resultant follows from Pythagoras:

resultant = square root of (first² + second²)

So 3 N and 4 N at right angles give 5 N, and 6 N and 8 N give 10 N. Both triangles are worth recognising on sight.

The resultant of two perpendicular forces is always larger than either one and smaller than their sum. Adding them (3 + 4 = 7) is right only for parallel forces, and subtracting them (4 − 3 = 1) only for opposite ones. Both wrong answers are usually on offer.

Common mistakes

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