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CIE 0620 Chemistry · IGCSE · Topic 4.1

Electrolysis

CIE 0620 ChemistryIGCSEFree revision notes

Contents: 10 sections

The cell and its vocabulary

Electrolysis is the decomposition of an ionic compound, when molten or in aqueous solution, by the passage of an electric current.

The compound must be molten or dissolved because its ions have to be free to move. A solid ionic compound holds its ions in fixed positions in the lattice, so it does not conduct and cannot be electrolysed.

Two rules cover every Core prediction:

Molten lead(II) bromide

Lead(II) bromide is heated until it melts, and inert graphite electrodes are dipped in.

This is the model for any molten binary compound, one that contains just two elements: the metal appears at the cathode and the non-metal at the anode. Molten zinc chloride gives zinc and chlorine; molten aluminium oxide gives aluminium and oxygen. No prediction is needed beyond reading the two elements out of the formula.

The lamp in the circuit only lights once the solid has melted, which is the observation that proves ions must be mobile.

Concentrated aqueous sodium chloride

Diagram walkthrough · 4 minElectrolysis of brine, from the four ions to the productsMaChemGuyLists all four ions present, sodium and chloride from the salt plus hydrogen and hydroxide from the water, then follows the electron round the circuit: chloride loses one at the anode giving chlorine, hydrogen gains one at the cathode giving hydrogen. It ends by explaining why hydrogen is discharged in preference to sodium, which is the reactivity point.

Sodium is not produced, even though it is the metal in the compound. In a solution there is also hydrogen present from the water, and hydrogen is less reactive than sodium, so hydrogen is discharged instead.

Dilute sulfuric acid

The overall effect is that water is being split, so the gases come off in a fixed ratio of 2 to 1:

2H₂O → 2H₂ + O₂

If 24 cm³ of hydrogen is collected, the volume of oxygen is 24 / 2 = 12 cm³. A question showing two collecting tubes is usually asking you to identify which gas is which from that ratio: the fuller tube is always the hydrogen.

Predicting the products in solution (Extended)

For aqueous solutions there are two things present at each electrode competing to be discharged, and the rules are:

Concept explainer · 2 minThe two rules for predicting products in solutionCognitoStates the two rules separately, which is why the topic confuses people. At the cathode the ion of the less reactive element is discharged, checked against the reactivity series; at the anode a halide wins if one is present and otherwise it is always the hydroxide.

At the cathode, the less reactive of the metal and hydrogen is produced.

At the anode, it depends on the ion and on the concentration.

ElectrolyteAt the cathodeAt the anode
Concentrated sodium chlorideHydrogenChlorine
Dilute sodium chlorideHydrogenOxygen
Copper(II) sulfateCopperOxygen
Dilute sulfuric acidHydrogenOxygen
Molten lead(II) bromideLeadBromine

The middle two rows carry the whole idea. Changing the concentration of sodium chloride changes the anode product without touching the cathode product, and swapping sodium for copper changes the cathode product without touching the anode product.

How charge is carried (Extended)

Three separate movements happen at once, and a full-mark answer names all three.

  1. In the external circuit: electrons flow from the negative terminal of the power supply to the cathode, and from the anode back to the positive terminal.
  2. In the electrolyte: ions move. Cations travel to the cathode and anions to the anode.
  3. At the electrodes: cations gain electrons at the cathode and anions lose electrons at the anode, so the circuit is completed.

Electrons never travel through the electrolyte, and ions never travel through the wires. Saying that electrons flow through the solution is a standard error and loses the mark.

Half-equations (Extended)

At the cathode, reduction, meaning gain of electrons:

At the anode, oxidation, meaning loss of electrons:

Check the last one both ways. Atoms: 4 oxygen and 4 hydrogen on the left, and on the right 2 in O₂ plus 2 in the water gives 4 oxygen, with 4 hydrogen. Charge: 4 × (−1) = −4 on the left, and 0 + 4 × (−1) = −4 on the right.

The number of electrons is always the charge on the ion times the number of ions, so a 2+ ion needs 2 electrons and two 1− ions release 2.

Aqueous copper(II) sulfate (Extended)

With inert carbon electrodes:

With copper electrodes:

The mass gained at the cathode equals the mass lost at the anode. If the cathode gains 0.64 g then the anode has lost 0.64 g, and this is the basis of purifying copper and of electroplating.

Common mistakes

Check you have it

Question 1

What is produced at each electrode during the electrolysis of aqueous solutions using inert electrodes? Each answer gives, in order: positive electrode (anode); negative electrode (cathode).

Table from the Cambridge Chemistry 0620 Paper 1 October/November 2023 paper, variant 1, question 9.

Question 2

Four substances are electrolysed using inert electrodes. Which row describes the electrode products? substance anode product cathode product Use the source image for S19 Paper 11, question 10.

Table from the Cambridge Chemistry 0620 Paper 1 May/June 2019 paper, variant 1, question 10.

Question 3

Concentrated aqueous sodium chloride is electrolysed using inert electrodes. Gases X and Y are produced at the electrodes shown. What are X and Y? Each answer gives, in order: X; Y.

Diagram from the Cambridge Chemistry 0620 Paper 1 May/June 2023 paper, variant 1, question 9.
What the syllabus asks for on this topicSyllabus points

Syllabus points

  • Define electrolysis as the decomposition of an ionic compound, when molten or in aqueous solution, by the passage of an electric current.
  • Identify the anode as the positive electrode, the cathode as the negative electrode, and the electrolyte as the substance being decomposed.
  • Identify the products and describe the observations for the electrolysis of molten lead(II) bromide, concentrated aqueous sodium chloride and dilute sulfuric acid, using inert electrodes.
  • State that metals or hydrogen form at the cathode and that non-metals other than hydrogen form at the anode, and predict the products for a molten binary compound.
  • Extended only: describe the transfer of charge during electrolysis, in the external circuit, at the electrodes and in the electrolyte, and predict the products for a halide solution that is dilute or concentrated.
  • Extended only: construct ionic half-equations for oxidation at the anode and reduction at the cathode, including the electrolysis of aqueous copper(II) sulfate with carbon and with copper electrodes.

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