CIE 0620 Chemistry · IGCSE · Topic 6.4

Redox

CIE 0620 ChemistryIGCSEFree revision notes

Contents: 9 sections

Roman numerals

A Roman numeral in a name gives the oxidation number of that element in that compound, and nothing else.

The numeral is not the number of atoms and not the charge on the whole compound. Iron(III) oxide is Fe<sub>2</sub>O<sub>3</sub>, which has three oxygens and two irons, and the III refers to neither count.

Core: the oxygen definitions

In the blast furnace:

Fe<sub>2</sub>O<sub>3</sub> + 3CO → 2Fe + 3CO<sub>2</sub>

Iron(III) oxide loses oxygen, so it is reduced. Carbon monoxide gains oxygen, so it is oxidised. Both happen in one equation, which is what makes it redox.

Two more to recognise on sight:

Extended only: the electron definitions

OIL RIG: Oxidation Is Loss, Reduction Is Gain, of electrons.

Mg → Mg<sup>2+</sup> + 2e<sup>−</sup> is oxidation, because magnesium loses two electrons.

Cl<sub>2</sub> + 2e<sup>−</sup> → 2Cl<sup>−</sup> is reduction, because each chlorine atom gains one electron.

The electron definition is the wider one. Every reaction that is redox by the oxygen definition is also redox by the electron definition, but many electron transfers involve no oxygen at all, such as magnesium burning in chlorine.

Extended only: oxidation numbers

Four rules cover everything the syllabus asks:

  1. An element on its own has oxidation number 0. That covers Mg, O<sub>2</sub>, Cl<sub>2</sub> and Fe.
  2. A simple ion has the oxidation number of its charge. Na<sup>+</sup> is +1, Cl<sup>−</sup> is −1, O<sup>2−</sup> is −2.
  3. In a compound, oxygen is usually −2 and hydrogen is usually +1.
  4. The oxidation numbers in a neutral compound sum to 0, and in an ion they sum to the charge on the ion.

Worked example. Find the oxidation number of manganese in KMnO<sub>4</sub>.

Potassium is +1 and there are four oxygens at −2 each:

contribution of the oxygens = 4 × (−2) = −8

oxidation number of manganese = 0 − 1 + 8 = +7

which is why the compound is named potassium manganate(VII).

Worked example. Find the oxidation number of chromium in Cr<sub>2</sub>O<sub>7</sub><sup>2−</sup>.

Seven oxygens contribute 7 × (−2) = −14, and the numbers must sum to −2:

total for the two chromiums = −2 + 14 = 12

oxidation number of each chromium = 12 / 2 = +6

A rise in oxidation number is oxidation. A fall is reduction. Applying that to the blast furnace equation above: iron falls from +3 to 0, so it is reduced, and carbon rises from +2 to +4, so it is oxidised. The two definitions agree, as they must.

Extended only: oxidising and reducing agents

The wording matters because the agent is the one doing the opposite of what its name suggests happening to it. In Cl<sub>2</sub> + 2KBr → 2KCl + Br<sub>2</sub>, chlorine is the oxidising agent: it oxidises bromide from −1 to 0 while chlorine itself falls from 0 to −1.

Common oxidising agents: oxygen, chlorine, acidified potassium manganate(VII).

Common reducing agents: hydrogen, carbon, carbon monoxide, reactive metals such as zinc, and iodide ions.

Extended only: the two colour tests

ReagentColour beforeColour afterWhat it shows
Acidified potassium manganate(VII)PurpleColourlessThe added substance is a reducing agent
Potassium iodide solutionColourlessBrownThe added substance is an oxidising agent

Read them by asking what happened to the reagent.

Acidified potassium manganate(VII) goes from purple to colourless because the manganese falls from +7 to +2. The manganate(VII) has been reduced, so whatever it was added to must have been the reducing agent.

Potassium iodide goes from colourless to brown because iodide ions are oxidised to iodine, 2I<sup>−</sup> → I<sub>2</sub> + 2e<sup>−</sup>. The iodide has been oxidised, so whatever it was added to must have been the oxidising agent.

Which reactions are not redox

Recognising the reactions where no oxidation number changes saves marks in multiple choice questions.

By contrast, displacement of one metal by another, the reaction of a metal with an acid, combustion, and electrolysis are always redox.

Common mistakes

Check you have it

Question 1

In which change is the sulfur, S, in sulfur(I) oxide, S2O, reduced? SO3 Use the source image for W20 Paper 11, question 21.

Table from the Cambridge Chemistry 0620 Paper 1 October/November 2020 paper, variant 1, question 21.

Question 2

In a blast furnace, iron(III) oxide is converted to iron and carbon monoxide is converted to carbon dioxide.
Fe2O3 + 3CO → 2Fe + 3CO2
What happens to each of these reactants?

Question 3

Coke (carbon) and limestone are two raw materials used in the extraction of iron from hematite. Which type of reaction occurs when each substance is heated during the process? Each answer gives, in order: coke; limestone.

Table from the Cambridge Chemistry 0620 Paper 1 February/March 2023 paper, variant 2, question 28.
What the syllabus asks for on this topicSyllabus points

Syllabus points

  • Use a Roman numeral to indicate the oxidation number of an element in a compound.
  • Define oxidation as the gain of oxygen and reduction as the loss of oxygen.
  • Identify redox reactions as reactions in which oxygen is both gained and lost.
  • Extended only: define oxidation as the loss of electrons and reduction as the gain of electrons.
  • Extended only: identify redox reactions from changes in oxidation number, and define an oxidising agent and a reducing agent.
  • Extended only: identify oxidation and reduction from the colour changes of acidified potassium manganate(VII) and of potassium iodide.

Related CIE 0620 Chemistry topics

Browse all CIE 0620 Chemistry revision notes →

Not the topic you were looking for? Describe what you are stuck on in your own words and we will take you to the notes that answer it.